find the value of x^3+1/x^3 if x^2+1/x^2=14
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x²+1/x²=14
=>x²+1/x²=16-2
=>x²+1/x²+2=16
=>x²+1/x²+2(x)(1/x)=16. [since 1=(x)(1/x)]
=>(x+1/x)²=16
=>x+(1/x)=√16
=>x+(1/x) =4
we know that a³+b³=(a+b)(a²-ab+b²)
there fore
x³+(1/x³)=(x+1/x)(x²-1+1/x²)
=>x³+1/x³=(4)(14-1) [since x²+1/x²=14]
=>x³+1/x³=(4)(13)
=>x³+1/x³=52
HOPE YOU UNDERSTAND THE ANSWER
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