find the value of x^3+1/x^3 if x^2+1/x^2=4
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Answer:
x^2+1/x^2=4
(x+1/x)^2-2x1/x=4
(x+1/x)^2=4+2=6
x+1/x=√6
x^3+1/x^3
=(x+1/x)^3-3x.1/x(x+1/x)
=(√6)^3-3.√6
=6√6-3√6=3√6
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