Question

Find the value of x.
(3/2)^3 (4/3^)-7 =(3/4)^2x​

Answer 1

Answer:

Hey dear!

Here is yr answer.........

(3/4)^³ × (4/3)^-7 = (3/4)^2x

[ a^-1 = 1/a^1 ]

(3/4)^3 × (3/4)^7 = (3/4)^2x

[a^m × a^n = a^m+n]

(3/4)^3+7 = (3/4)^2x

(3/4)^10 = (3/4)^2x

Here, bases are equal, so the powers must be equal!

10 = 2x

x = 10/2

x = 5

Hope it hlpz.....