Question

find the value of x: 3^2x*3^x*3 * 3,^4-x = (√3)^10
a)-1
b)0
c)1
d)2​

Answer 1

Answer:

x=3+2

2

x

1

=

3+2

2

1

×

3−2

2

3−2

2

=3−2

2

(

x

−

2

1

)

2

=x+

x

1

−2

=3+2

2

+3−2

2

−2=4

So,

x

−

x

1

=

4

=±12