Question

find the value of x^3-7x^2+21x-10for x=-2​

Answer 1

Answer:

${x}^{3} - 7 {x}^{2} + 21x - 10 \\ where \: x = -2 \\ then \\ - {2}^{3} - 7 \times {-2}^{2} + 21 \times -2 - 10 \\ = -8-28-42-10 \\ = -88$

Answer 2

Step-by-step explanation:

put value of x in eq.

(-2)^3-7 (-2)^2+21 (-2)-10

= -8-28-42-10

= -88