Math, asked by applehoney2600, 1 year ago

Find the value of x^3-8y^3-36xy-216When x=2y+6

Answers

Answered by littyissacpe8b60
0

x³ - 8y³ - 36xy - 216

x= 2y + 6

(2y+6)³ - 8³ - 36y(2y+6) - 216

= 8y³ + 216 + 72y² + 216y - 8x³ - 72y² - 216y - 216

= 0

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