Question

find the value of x^3. dare to solve it​

Answer 1

Answer:

$x^{3}=1$

Step-by-step explanation:

Given,

$x^{2}+x+1=0$

Multiplying both sides by $(x-1)$ we get,

$(x-1)(x^{2}+x+1)=0(x-1)\\\implies (x-1)(x^{2}+x+1)=0\\\implies x^{3}-1^{3}=0 \,[(a-b)(a^{2}+ab+b^{2})=a^{3}-b^{3}]\\\implies \boxed {\bf x^{3}=1}$

Hope this helps! Please mark my answer as Brainliest!

(arunajoshi2150's answer is wrong)