Find the value of x^3 for which x^-3 = 7
'^' stands for power
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Answer:
7x−3+73−x=507
Let 7x−3=y; Then 73−x=1y
y+1y=507
Solving we get y=7 or 7−1
Wheny=7 , x−3=1 ;x=4
When y=7−1,x−3==1 ; x=2
Answered by
1
Answer is 7. Need Explanation?
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