Find the value of x^3_y^3_12xy_64,when x_y_4=0
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hey mate
here is the answer...
Answer:
x-y-4=0
x-y=4
cubing on both sides,
(x-y)³=(4)³
x³-y³-3xy(x-y)=64
x³-y³-3xy(4)=64
x³-y³-12xy-64=0
thus,
0 is the answer...
Answered by
0
here is the answer is zero
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