Math, asked by dakshthakran05, 10 months ago

Find the value of x^3_y^3_12xy_64,when x_y_4=0

Answers

Answered by Anonymous
0

hey mate

here is the answer...

Answer:

x-y-4=0

x-y=4

cubing on both sides,

(x-y)³=(4)³

x³-y³-3xy(x-y)=64

x³-y³-3xy(4)=64

x³-y³-12xy-64=0

thus,

0 is the answer...

Answered by thelu
0

here is the answer is zero

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