Find the value of x^3+y^3+12xy-64 when x+y=4
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x^3 + y^3 + 12xy -64 .... (I)
given : x+y = 4
we know that, x^3 + y^3 = ( x+y)^3 - 3xy (x+y)
therefore, equation can be written as
(x+y) ^3 - 3xy(x+y) -12xy +64
put the value of x+y as -4 we get
(-4)^3 - 3xy( -4) - 12xy +64
-64 +12xy -12xy +64 = 0
hope this answer help you
given : x+y = 4
we know that, x^3 + y^3 = ( x+y)^3 - 3xy (x+y)
therefore, equation can be written as
(x+y) ^3 - 3xy(x+y) -12xy +64
put the value of x+y as -4 we get
(-4)^3 - 3xy( -4) - 12xy +64
-64 +12xy -12xy +64 = 0
hope this answer help you
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Pranavjain2750:
It did help me! Thanks!!
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