Math, asked by preetramgarhia, 1 year ago

find the value of x^3+y^3-12xy+64 when x+y =-4

Answers

Answered by rsakshisrivasta
7
x+y=-4
x=-(4+y)
{-(4+y)} ^3+y^3-12(-4-y) y+64
-64-y^3-48y-12y^2+y^3+48y+12y^2+64 = 0
Answered by awaizking
1

Answer:

Step-by-step explanation:

Attachments:
Similar questions