find the value of x^3 + y^3 +6xy - 8 when y= 2-x
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Answer :
When y = 2 - x,
x³ + y³ + 6xy - 8
= x³ + (2 - x)³ + 6x (2 - x) - 8
= x³ + 8 - 12x + 6x² - x³ + 12x - 6x² - 8
= 0
Hope it helps! (:
When y = 2 - x,
x³ + y³ + 6xy - 8
= x³ + (2 - x)³ + 6x (2 - x) - 8
= x³ + 8 - 12x + 6x² - x³ + 12x - 6x² - 8
= 0
Hope it helps! (:
Raghav1111111111:
ur answer is wrong
@varun, my answer is correct... don't worry ☺
thanks very much yours is 100 per cent correct answer
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