Question

find the value of x^3+y^3+9xy-27

Answer 1

from the above

x+y=3
cube both sides
(3)^3=(x+y)^3
27=x3+y3+3xy(x+y)
27=x3+y3+3xy(3)
27=x3+y3+9xy ......... (1)
x3+y3+9xy-27
from equation (1)
27-27
0

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