Question

Find the value of x^3+y^3+z^3-3xyz if x^2+y^2+z^2=84 and x+y+z=15​

Answer 1

Answer:

2x+3=x+15

Step 1: Subtract x from both sides.

2x+3−x=x+15−x

x+3=15

Step 2: Subtract 3 from both sides.

x+3−3=15−3

x=12

Answer:

x=12