Question

find the value of x⁰​

Answer 1

Step-by-step explanation:

3x + 10 degree = 2x degree

3x + 2x = 10 degree

5x = 10 degree

x = 10 degre / 5x

x = 2 x

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Answer 2

Answer:

Given that

∆OAB

then AB=AO[lsosceless triangle]

angle B=angle AOB

then (3x+10)°=angle AOB

BO+angle AOB=angle COD [vertically opposite angles]

(3x+10)°=angle COD

Now consider,

∆OCD,

OC=CD[lsosceless triangle]

angle COD=angle D

(3x+10)°=angle D

therefore, angle COD+angle ODC+angle OCD=180°[angle sum property]

3x+10+3x+10+2x=180°

8x+20=180°-20°

8x=160°

x=160÷8

then x=20°

therefore x°=20°

8x=180°