find the value of x.
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heya mate hope it helps u
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Heya
(-7/8)^2+x = (-7/8)^3 [(-7/8)^2/3 ÷ (-7/8)^-1/3]
=> (-7/8)^2+x = (-7/8)^3 [(-7/8)^2+1/3]
=> (-7/8)^2+x = (-7/8)^3 [(-7/8)^3/3]
=> (-7/8)^2+x = (-7/8)^3 × (-7/8)
=> (-7/8)^2+x = (-7/8)^3+1
=> (-7/8)^2+x = (-7/8)^4
Since bases are same.
=> 2 + x = 4
=> x = 4 - 2
=> x = 2
Thanks
(-7/8)^2+x = (-7/8)^3 [(-7/8)^2/3 ÷ (-7/8)^-1/3]
=> (-7/8)^2+x = (-7/8)^3 [(-7/8)^2+1/3]
=> (-7/8)^2+x = (-7/8)^3 [(-7/8)^3/3]
=> (-7/8)^2+x = (-7/8)^3 × (-7/8)
=> (-7/8)^2+x = (-7/8)^3+1
=> (-7/8)^2+x = (-7/8)^4
Since bases are same.
=> 2 + x = 4
=> x = 4 - 2
=> x = 2
Thanks
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