find the value of x
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x=3+2
2
x
1
=
3+2
2
1
×
3−2
2
3−2
2
=3−2
2
(
x
−
2
1
)
2
=x+
x
1
−2
=3+2
2
+3−2
2
−2=4
So,
x
−
x
1
=
4
=±12 Ans
Answered by
0
We know that,
b=(a+c)/2
Where a,b,c are consecutive terms of an AP
So,
2x=((x+1)+(3x-1))/2
4x=x+1+3x-1
4x=4x+0
4x-4x=0
0=0
But we need to find the value of x
There is something wrong in this question
b=(a+c)/2
Where a,b,c are consecutive terms of an AP
So,
2x=((x+1)+(3x-1))/2
4x=x+1+3x-1
4x=4x+0
4x-4x=0
0=0
But we need to find the value of x
There is something wrong in this question
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