Question

Find the value of x.....​

Answer 1

Answer:

ans is

135 plz mark me brainliest

Answer 2

Answer :-

The value of x is 65°.

Step-by-step explanation:-

To Find,

• The value of x

Solution,

Given that,

• ∠SPR = 135°
• ∠TQP = 110°

Figure,

• Refer the attachment

A . T . Q

First we need to find out the interior angles

• ∠QPR
• ∠RQP

The measure of ∠QPR is,

➮ ∠QPR + ∠SPR = 180° .... linear pair

➮ ∠QPR + 135° = 180°

➮ ∠QPR = 180° - 135°

➮ ∠QPR = 45°

The measure of ∠RQP is,

➮ ∠RQP + TQP = 180° .... linear pair

➮ ∠RQP + 110° = 180°

➮ ∠RQP = 180° - 110°

➮ ∠RQP = 70°

Therefore, the value of x is,

➮ ∠RQP + ∠QPR + x = 180° ... angle sum property of triangle

➮ 70° + 45° + x = 180°

➮ 115° + x = 180°

➮ x = 180° - 115°

➮ x = 65° ★

Hence, the value of x is 65°.

Now, Verification

➮ 70° + 45° + 65° = 180°

➮ 70 + 110 = 180

➮ 180 = 180

L.H.S = R.H.S

Hence, Verified !