Question

find the value of x ​

Answer 1

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$\longrightarrow \sf \bigg( \frac{3}{4} {\bigg)}^{2x + 1} = \bigg( { \frac{3}{4}\bigg) }^{3} \\ \\\longrightarrow \sf2x + 1 = 3 \\ \\\longrightarrow \sf 2x = 3 - 1 \\ \\\longrightarrow \sf 2x = 2 \\ \\\longrightarrow \sf x = \frac{2}{2} \\ \\\longrightarrow \boxed{\sf x = 1}$

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$\longrightarrow \sf\bigg( { \frac{9}{4}\bigg) }^{3} \times \bigg( { \frac{8}{9}\bigg) }^{3} = {2}^{6x} \\ \\\longrightarrow \sf \bigg( { \frac{9}{4} \times \frac{8}{9} \bigg) }^{3} = {2}^{6x} \\ \\\longrightarrow \sf {2}^{3} = {2}^{6x} \\ \\ \longrightarrow \sf3 = 6x \\ \\\longrightarrow \sf x = \frac{3}{6} \\ \\\longrightarrow \boxed{\sf x = \frac{1}{2} }$