Question

find the value of x​

Answer 1

Answer:

50°

Step-by-step explanation:

x+130°=180° (Linear Pair)

=> x = 50°

Answer 2

Correct Question-:

• Find the value of x .

Figure 1 -:

$\setlength{\unitlength}{1 cm}\begin{picture}(0,0)\thicklines\put(5,1){\vector(1,0){4}}\put(5,1){\vector(-1,0){4}}\put(5,1){\vector(1,1){3}}\put(2,2){ \underline{\boxed{\large\sf 130 + x = 180^{\circ}} }}\put(4.5,1.3){ \sf 130^{\circ} }\put(5.7,1.3){ \sf x^{\circ} }\end{picture}$

AnswEr-:

• $\underline{\boxed{\star{\sf{\blue{ The\:Value \:of\:x \:is = \: 50⁰ }}}}}$

Explanation-:

Given-:

• The first angle is of 130⁰

To Find-:

• The value of x .

Analysis,

• As, we can see that in the figure 1 that the angle is forming a Linear Pair . The sum of Linear Pair is 180⁰.

• $\underline{\boxed{\star{\sf{\blue{ Linear \: Pair\: = Angle_{A}\: + Angle_{B}=180⁰}}}}}$

$\setlength{\unitlength}{1 cm}\begin{picture}(0,0)\thicklines\put(5,1){\vector(1,0){4}}\put(5,1){\vector(-1,0){4}}\put(5,1){\vector(1,1){3}}\put(2,2){ \underline{\boxed{\large\sf a + b = 180^{\circ}} }}\put(4.5,1.3){ \sf a^{\circ} }\put(5.7,1.3){ \sf b^{\circ} }\end{picture}$

Here ,

• Angle A = 130⁰
• Angle B = x

Now ,

• $\implies{\sf{\large {130⁰ + x = 180⁰}}}$
• $\implies{\sf{\large {x = 180⁰-130⁰}}}$
• $\implies{\sf{\large { x = 50⁰}}}$

Hence ,

• $\underline{\boxed{\star{\sf{\blue{ The\:Value \:of\:x \:is = \: 50⁰ }}}}}$

$\setlength{\unitlength}{1 cm}\begin{picture}(0,0)\thicklines\put(5,1){\vector(1,0){4}}\put(5,1){\vector(-1,0){4}}\put(5,1){\vector(1,1){3}}\put(2,2){ \underline{\boxed{\large\sf 130 + 50 = 180^{\circ}} }}\put(4.5,1.3){ \sf 130^{\circ} }\put(5.7,1.3){ \sf 50^{\circ} }\end{picture}$

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More to know about Linear Pair-:

• The angles are only said to be Linear Pair when the angles are adjacent to each other when they are interested by two lines .
• The sum of angles of a linear pair is always equal to 180°. 

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Note Down ♤ -:

• Please see this answer in website .

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