Question

Find the value of x. ​

Answer 1

Answer:

72 degree

Step-by-step explanation:

<RTQ+<PTQ=180 (linear pair)

90+<PTQ=180

<PTQ=90

IN TRIANGLE PTO

<TPO+PTO+<TOP=180( ANGLE SUM PROP.)

<30+90+<POT= 180

120+<PTO= 180

<PTO= 60

<PTO=SOQ (V.O.A)

X+<SQO+<SOQ=180

X+48+60=180

X+108=180

X= 72 DEGREE

Answer 2

Answer:

x= 72°

Step-by-step explanation:

IN ∆QTR

by angle sum property

LTQR + LQTR + LTRQ = 180°

48° +90° + LTRQ = 180°

LTRQ = 180 °-138°

LTRQ = 42°

IN ∆ PSR

BY angle sum property

LSPR +LPRS + LRSP = 180°

30°+42°+LRSP = 180°

LRSP = 180°-72°

LRSP = 108°

ON LINE SEGMENT QR

LQSP + LPSR =180° (LINEAR PAIR )

x° +108° = 180°

x=180°-108°

x° = 72°

HOPE THIS HELPS YOU .