Question

find the value of x.........

Answer 1

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Answer 2

${2}^{3} ( {6}^{0} + {3}^{2x} ) = 8 \\ 8 ( 1 + {3}^{2x} ) = 8 \\ on \: divnding \: both \: sides \: by \: 8 \: gives \\ 1 + {3}^{2x} = 1 \\ {3}^{2x} = 1 - 1 = 0 \\ {3}^{2x} = {3}^{0} \\ 2x = 0 \\ on \: dividing \: both \: sides \: by \: 2 \: gives \\ x = 0$