find the value of x 3x^2+12x=135
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3x^2 + 12x -135 = 0
3 (x^2 + 4x - 45) = 0
x^2 + 4x - 45 = 0
x^2 - 5x + 9x - 45 = 0
x( x -5)+9 (x-5) = 0
(x -5)(x+9) = 0
x = 5 or -9
Hope you like this answer. ..........
3 (x^2 + 4x - 45) = 0
x^2 + 4x - 45 = 0
x^2 - 5x + 9x - 45 = 0
x( x -5)+9 (x-5) = 0
(x -5)(x+9) = 0
x = 5 or -9
Hope you like this answer. ..........
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