Math, asked by naredalakhan, 8 months ago

Find the value of x
3x^3 - 2x²-x=0​

Answers

Answered by itscraze
1

Step-by-step explanation:

x (3x^2 -2x-1) =0

x ( 3x^2 - 3x + 1x -1 ) = 0

x( 3x( x - 1 ) + 1 ( x - 1 ) = 0

x ( 3x + 1 ) ( x - 1 ) = 0

x(-1/3 )(1)

x× -1/3 = 0

x = -3

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Answered by ksangameshwar14
0

Answer:

given 3x^3-2x^2-x=0.....(1)

Step-by-step explanation:

by taking x common x(3x^2-2x-1)=0. Now 3x^2-2x-1 eqn written has 3x^2-3x+x-1 = 0. Now x(x-1)(3x+1)=0.then the required values of x are x = 0(or) 3 (or) -1/3

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