Question

Find the value of x,( 4/5 )^8 X ( 4/5 )^7=(4/5)^(2x+1)​

Answer 1

Answer:

7

Step-by-step explanation:

( 4/5 )^8 X ( 4/5 )^7=(4/5)^(2x+1)

(4/5)^15 = (4/5)^(2x+1)

equating the exponents we get,

2x+1 = 15

2x= 14

x= 7

Answer 2

We have,

$(\frac{4}{5})^{8} \times (\frac{4}{5})^{7} = (\frac{4}{5})^{2x + 1}$

= 2x + 1 = 8 + 7

(because if a^n × a^m = a^(n + m) and if a^n = a^m then n = m)

= 2x + 1 = 15

= 2x = 14

= x = 7

Thus the value of x in the equation is 7