Question

Find the value of x (4/7)^3÷(343/64)^2x-1=16/49

Answer 1

solution:-

${( \frac{4}{7}) }^{ 3} \div {( \frac{343}{64}) }^{2x - 1} = \frac{16}{49} \\ {( \frac{4}{7} )}^{3} \times {( \frac{4}{7}) }^{6x - 3} = \frac{16}{49} \\ ( { \frac{4}{3} )}^{6x} = ( { \frac{4}{7}) }^{2} \\ 6x = 2 \\ x = \frac{2}{6} \\ x = \frac{1}{3}$

Answer 2

Answer:

Refer to the above attachment and mark as BRAINLIEST plz...