Question

find the value of x:​

Answer 1

Answer:

CAD= CDA= (180-56)÷2 =62

ADB= 180-62= 118

DAB=DBA= (180-118)÷2 = 31

BAC=BAD+DAC=31+62= 93

Step-by-step explanation:

The summation of three angles of a triangle is 180 degrees..

Hope it will be helpful

Answer 2

Answer

In the given figure, we are given with a triangle that has two partitions which forms two other triangles. On the triangle on right side, we are given with one of the angle and we are also said that, it's a isosceles triangle. In the figure attached in the answer, we are given with two other angles marked as y. First, we'll find the value of those angles.

Value of ∠y :-

$\sf \leadsto {Angle \: sum \: property}_{(Triangle)} = {180}^{\circ}$

$\sf \leadsto {56}^{\circ} + y + y = {180}^{\circ}$

$\sf \leadsto 56 + 2y = 180$

$\sf \leadsto 2y = 180 - 56$

$\sf \leadsto 2y = 124$

$\sf \leadsto y = \dfrac{124}{2}$

$\sf \leadsto y = {62}^{\circ}$

Now, we should find the value of ∠a.

Value of ∠a :-

$\sf \leadsto Straight \: line \: angle = {180}^{\circ}$

$\sf \leadsto {62}^{\circ} + \angle{a} = {180}^{\circ}$

$\sf \leadsto \angle{a} = 180 - 62$

$\sf \leadsto \angle{a} = {118}^{\circ}$

Now, we can find the value of ∠x.

Value of ∠x :-

$\sf \leadsto {Angle \: sum \: property}_{(Triangle)} = {180}^{\circ}$

$\sf \leadsto {118}^{\circ} + x + x = {180}^{\circ}$

$\sf \leadsto 118 + 2x = 180$

$\sf \leadsto 2x = 180 - 118$

$\sf \leadsto 2x = 62$

$\sf \leadsto x = \dfrac{62}{2}$

$\sf \leadsto x = {31}^{\circ}$

Therefore, the value of ∠x is 31°.