Question

Find the value of X
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Answer 1

ax² + bx + c = 0

With quadratic formula

x₁ , ₂ = $\sf{{\dfrac{-b±{\sqrt{b²-4ac}}}{2a}}}$

x = $\sf{{\dfrac{-b+{\sqrt{b²-4ac}}}{2a}}}$ a ≠ 0

x = $\sf{{\dfrac{-b-{\sqrt{b²-4ac}}}{2a}}}$ a ≠ 0