Question

find the value of x ? 5^2×+1 ÷ 25 = 5^3​

Answer 1

Step-by-step explanation:

${5}^{2x + 1} \div 25 = {5}^{3} \\ {5}^{2x + 1} + {5}^{2} = {5}^{3} \\ as \: base \: are \: equal \: then \: power \: will \: also \: equal \\ so2x + 1 - 2 = 3 \\ 2x - 1 = 3 \\ 2x = 3 + 1 \\ 2x = 4 \\ x = \frac{4}{2 } \\ x = 2$

So answer is 2

Answer 2

HERE IS UR ANSWER DEAR,

$\frac{ {5}^{2x + 1} }{25} = {5}^{3}$

$here....25 = {5}^{2}$

$so$

$\frac{ {5}^{2x + 1} }{ {5}^{2} } = {5}^{3}$

${5}^{2x + 1} = {5}^{3} \times {5}^{2}$

${5}^{2x + 1} = {5}^{5}$

$bases \: are \: same$

$so \: we \: can \: equate \: the \: powers$

$2x + 1 = 5$

$2x = 5 - 1$

$2x = 4$

$x = \frac{4}{2}$

$x = 2$

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