Question

find the value of x
5^2x+1 ÷ 25 = 125​

Answer 1

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$\longmapsto \sf {5}^{2x + 1} \div 25 = 125$

$\longmapsto \sf {5}^{2x + 1} \div {5}^{2} = {5}^{3}$

$\longmapsto \sf {5}^{2x + 1 - 2} = {5}^{3}$

$\longmapsto \sf {5}^{2x - 1} = {5}^{3}$

$\longmapsto \sf2x - 1 = 3$

$\longmapsto \sf2x = 3 + 1$

$\longmapsto \sf2x = 4$

$\longmapsto \sf x = \frac{4}{2}$

$\longmapsto \boxed{ \sf x = 2}$