find the value of x^5 at x=2?
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Step-by-step explanation:
First, distribute x in parentheses
x(x+5)=2 becomes x^2 + 5x = 2
Then put all numbers to one side
x^2 + 5x -2 = 0
Since this can’t be factored, I would use the quadratic equation or by completing the square. I am going to be using completing the square.
So put the last number back to the other side
x^2 + 5x = 2
Now do (5/2)^2 = 6.25
Add 6.25 to each side
x^2 + 5x + 6.25 = 8.25
Now you can factor it and it becomes
(x+2.5)^2 = 8.25
Square root both sides
x+2.5 = √8.25
√8.25 is about 2.87 and since it is a square root it can be + or -
so x = (+ or - 2.87) - 2.5
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