Question

Find the value of x .
5x^2 + 2.7x + 0.108 = 0​

Answer 1

Answer :-

Value of x is (2.7 + √5.13)/10 or (2.7 - √5.13)/10

Explanation :-

Given equation :

5x² - 2.7x + 0.108 = 0

Comparing with ax² + bx + c = 0 we get

• a = 5

• b = - 2.7

• c = 0.108

Discriminant = D = b² - 4ac = (-2.7)² - 4(5)(0.108) = 7.29 - 2.16 = 5.13

Here D > 0

So we have two distinct real roots

Finding roots of the equation using quadratic formula

x = (-b ± √D)/2a

⇒ x = { - (-2.7) ± √5.13}/2(5)

⇒ x = (2.7 ± √5.13)/10

⇒ x = (2.7 + √5.13)/10 or (2.7 - √5.13)/10

∴ the value of x is (2.7 + √5.13)/10 or (2.7 - √5.13)/10

Answer 2

Answer:

I hope this help you