Math, asked by harsh5576, 7 months ago

find the value of x. 6^0÷6^-1=6x​

Answers

Answered by Anonymous
1

Answer:

x = 1

Step-by-step explanation:

Given an eqn such that,

 {6}^{0}   \div  {6}^{ - 1}  = 6x

To find the value of x.

We know that,

  • a^0 = 1

Therefore, we will get,

=> 1 ÷ 6^(-1) = 6x

=> 1/6^(-1) = 6x

But, we know that,

  • a^(-m) = 1/a^m

Therefore, we will get,

=> 1/(1/6) = 6x

=> 6 = 6x

=> 6x = 6

=> x = 6/6

=> x = 1

Hence, the required value of x = 1.

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