Question

find the value of x^6+x^5-x^4+x^3-x^2+x-1 for x=(-1)​

Answer 1

Answer:

-5

Step-by-step explanation:

x=(-1)

p(x)=x⁶+x⁵-x⁴+x³-x²+x-1

p(-1)= (-1)⁶+(-1)⁵-(-1)⁴+(-1)³-(-1)²+(-1)-1

p(-1)=1-1-1-1-1-1-1

p(-1)=-5(answer)

Answer 2

Answer:

The value of the expression $x^6+x^5-x^4+x^3-x^2+x-1$ at $x=-1$ is $-5$.

Step-by-step explanation:

The given polynomial is

$x^6+x^5-x^4+x^3-x^2+x-1$

We need to find the value of the polynomial at $x=-1$.

Note that the even powers of -1 are 1and the odd powers of -1 are -1. So substituting $x=-1$ in the polynomial, we obtain,

$(-1)^6+(-1)^5-(-1)^4+(-1)^3-(-1)^2+(-1)-1\\\\=1+(-1)-(1)+(-1)-(1)+(-1)-1 = 1-1-1-1-1-1-1=-5$

So the value of the expression at $x=-1$ is $-5$.