Question

find the value of x (-7/5)^11÷(-7/5)^3=(-7/5)^2x+2​

Answer 1

Answer:

x=3

Step-by-step explanation:

Using identity a^m ÷ a^n = a^(m-n)

(-7/5)^(11-3) = (-7/5)^(2x+2)

(-7/5)^(8) = (-7/5)^(2x+2)

On equating,

8 = 2x+2

Or,

2x+2 = 8

2x = 8-2

2x = 6

x=6÷2

x=3

Answer 2

According to the question

The given equation is

$\frac{(-\frac{7}{5} )^{11} }{(-\frac{7}{5} )^{3}} =(-\frac{7}{5} )^{2x+2}$

Find the value of $x$

$\frac{(-\frac{7}{5} )^{11} }{(-\frac{7}{5} )^{3}} =(-\frac{7}{5} )^{2x+2}$

So, $(-\frac{7}{5} )^{11-3}=(-\frac{7}{5} )^{2x+2}$

$(-\frac{7}{5} )^{8}=(-\frac{7}{5} )^{2x+2}$

On comparision

$2x+2=8$

$2x=8-2$

$2x=6$

$x=3$

So, the value of $x=3.$