Math, asked by s2385kailashs00156, 6 hours ago

Find the value of X, ( 7x-7 ) / (7) = (4x+2) / (2) * 2 points
a)-2
b) 2
c)0
d) 1​

Answers

Answered by su527396
0

Answer:

d

Step-by-step explanation:

welcome for my answer hi how are you

Answered by CɛƖɛxtríα
88

The value of x is –2 (option a).

Step-by-step explanation:

In the question, an algebraic equation has been given and we've been asked to find the value of the unknown variable in the equation. The algebraic equation is:

 \qquad \qquad\boxed{ \sf{ \dfrac{7x - 7}{7} =  \dfrac{4x + 2}{2}  }}

The value of x has to be found here. In order to find its value, we have to write the equation neatly, first.

 \twoheadrightarrow \quad{ \bf{ \dfrac{7x - 7}{7} =  \dfrac{4x + 2}{2}  }}

Since the values in the L.H.S. and the R.H.S. are in fractional form, they can be cross-multiplied here.

 \twoheadrightarrow \quad{ \bf{2(7x - 7) = 7(4x + 2)}}

Now, the numbers 2 and 7 should be multiplied with their respective set of expressions given in brackets.

 \twoheadrightarrow \quad{ \bf{14x - 14 = 28x + 14}}

Since the values of L.H.S. and the R.H.S. cannot be further simplified, transposition can be performed here. So, let's transpose 28x to the L.H.S. and –14 to the L.H.S. On transposing, 28x will be changed as –28x and –14 will be changed as 14.

 \twoheadrightarrow \quad{ \bf{14x - 28x = 14 + 14}}

Subtracting the terms 14x and 28x in the L.H.S.

 \twoheadrightarrow \quad{ \bf{ - 14x = 14 + 14}}

And adding the numericals 14 and 14 in the R.H.S.

 \twoheadrightarrow \quad{ \bf{ - 14x =28}}

Again the like terms has to be transposed. So, 14 is divided in the R.H.S.

 \twoheadrightarrow \quad{ \bf{ -x  =    \dfrac{28}{14} }}

Simplifying the value of R.H.S. by reducing fraction to its lowest form.

 \twoheadrightarrow \quad{ \bf{- x  =    \dfrac{2}{1} }}

Which can be also be written as,

 \twoheadrightarrow  \quad\underline{ \boxed{ \frak \red{ \pmb{ x  =  - 2}}}}

The value of x equals to 2. Hence, 1st option is appropriate.

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