Math, asked by harshita3265, 11 months ago

find the value of x ​

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Answered by daluckyseven2123
0

Step-by-step explanation:

3^{-5}\cdot \:3^{2x+1}=3^{13}+3^7

\frac{3^{-5}\cdot \:3^{2x+1}}{3^{-5}}=\frac{3^{13}}{3^{-5}}+\frac{3^7}{3^{-5}}

3^{2x+1}=\frac{3^{13}+3^7}{3^{-5}}

3^{2x+1}=387951930

\ln \left(3^{2x+1}\right)=\ln \left(387951930\right)

\left(2x+1\right)\ln \left(3\right)=\ln \left(387951930\right)

x=\frac{\ln \left(129317310\right)}{2\ln \left(3\right)}

you can check the extended steps here: https://www.symbolab.com/solver/pre-algebra-calculator/3%5E%7B-5%7D%5Ccdot3%5E%7B2x%2B1%7D%3D3%5E%7B13%7D%2B3%5E%7B7%7D


harshita3265: i am sorry to say that answer is 5
daluckyseven2123: it's ok.
daluckyseven2123: ok but how the heck the answer is 5?
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