Question

find the value of x ​

Answer 1

Answer:

Step-by-step explanation:

Sorry

Answer 2

Answer:

4x^2+4bx-(a^2-b^2)=0

4x^2+4bx-a^2+b^2=0

then

(2x+b)^2-a^2=0

(2x+b-a)(2x+b+a)=0

2x+b-a=0

2x=a-b

X=a-b/2