Question

find the value of x. a. 2^x=32 b. 3^x+1 =81​

Answer 1

Answer:

Hello mate..

Step-by-step explanation:

The value of x is 4

Step-by-step explanation:

Given the equation

(\frac{2}{3})^x\times (\frac{3}{2})^{2x}=\frac{81}{16}

\text{As, }x^a=\frac{1}{x^{-a}}

(\frac{3}{2})^{-x}\times (\frac{3}{2})^{2x}=\frac{81}{16}

\text{As, }x^a\times x^b=x^{a+b}

(\frac{3}{2})^{-x+2x}=\frac{81}{16}

(\frac{3}{2})^{x}=\frac{3^4}{2^4}

(\frac{3}{2})^{x}=(\frac{3}{2})^4

Comparing both sides, we get

x=4

Hence, the value of x is 4

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Answer 2

Answer:

a.16 b.80/3

Step-by-step explanation:

a. => 2x=32

=> x=32/2

=> x=16

b.=> 3x+1=81

=>3x=81-1=80

=> x=80/3

HOPE IT WILL HELP YOU