Find the value of (x^a÷x^b)^a+b×(x^b÷x^c)^b+c×(x^c÷x^a)^c+a
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Answer:
1
Step-by-step explanation:
(x^a-b)^a+b * (x^b-c)^b+c * (x^c-a)^c+a
x^(a^2-b^2) * x^(b^2-c^2) * x^(c^2-a^2)
x^(a^2-b^2+b^2-c^2+c^2-a^2)
x^0 = 1
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