Find the value of (x - a) + (x - b) + (x - c)' - 3 (x - a) (x - b) (x - 2), when
a+b+c=3x. .
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Step-by-step explanation:
=x-a+x-b+x-c-3(x^2-bx-ax+ab)(x-2)
=x-a+x-b+x-c-3(x^3-2x^2-bx^2+2bx-ax^2+2ax+abx-2ab)
=x-a+x-b+x-c-3x^3+6x^2+3bx^2-6bx+3ax^2-6ax-3abx+6ab
=3x-a-b-c-3x^3+6x^2+3bx^2-6bx+3ax^2-6ax-3abx+6ab
here is ur answer mate follow me
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