Find the value of X and all the angles of the triangle shown below.
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In ∆ PQR,
angle RPO = angle PRQ + angle RQP { exterior angle property }
=> ( x + 50 )° = ( 3x + 10 )° + ( 5x - 9 )°
=> 50° - 10° + 9° = 3x + 5x - x
=> 49° = 7x
=> x = 7°
angle RPO = ( x + 50 )°
= 57°
angle PRQ = ( 3x + 10 )°
- = 31°
angle RQP = ( 5x - 9 )°
= 26°
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