Question

Find the value of x and angles of the triangle

Answer 1

THE SUM OF THREE ANGLE OF A TRIANGLE IS 180 °.

SO.

2x-30 + 3x-50 + x+20 = 180.

6x -60 =180.

x-10 =30.

X= 40.

Angles are...(2 *40 -30)= 50°.

(3 *40 - 50) = 70°. (40+20)= 60°.

Answer 2

Concept:

Sum of all the interior angles is 180°.

Given:

The given angles are:

A=(2x-30)°

B=(3x-50)°

C=(x+20)°

To find:

We need to find the value of x.

Values of A, B and C.

Solution:

Now, the sum of all the interior angles is 180°.

Therefore,

∠A+∠B+∠C=180°

We know,

(2x-30)°+(3x-50)°+(x+20)°=180°

⇒2x+3x+x-30-50+20=180

⇒6x-60=180

⇒6x=180+60

⇒6x=240

⇒x=$\frac{240}{6}$=40°

Therefore, the value of x is 40°

Now, substituting values of x in angles of A, B and C.

For A,

∠A=2x-30

⇒∠A=2×40-30=80-30

⇒∠A=50°

For B,

∠B=3x-50

⇒∠B=3×40-50=120-50

⇒∠B=70°

For C,

∠C=x+20

⇒∠C=40+20

⇒∠C=60°

Therefore values of A, B and C are 50°, 70° and 60° respectively.