Question

find the value of x and answer me immediately
​

Answer 1

GIven:

$\sqrt{ \bigg(5^0 + \dfrac{2}{3} \bigg) } = (0.6)^2 - 3x$

To FInd:

The value of x

Solution:

$\sqrt{ \bigg(5^0 + \dfrac{2}{3} \bigg) } = (0.6)^2 - 3x$

Rewriting 5⁰ = 1:

$\sqrt{ \bigg(1 + \dfrac{2}{3} \bigg) } = (0.6)^2 - 3x$

$\sqrt{ \dfrac{5}{3} }= (0.6)^2 - 3x$

Rationalise the LHS by multiplying √3/√3:

$\dfrac{\sqrt{15} }{3} = (0.6)^2 - 3x$

Rewriting (0.6)² as a fraction:

$\dfrac{\sqrt{15} }{3} = \bigg( \dfrac{6}{10} \bigg)^2 - 3x$

$\dfrac{\sqrt{15} }{3} = \dfrac{9}{25} - 3x$

Multiply both sides by 3:

$\sqrt{15} = \dfrac{27}{25} - 9x$

Find x:

$9x = \dfrac{27}{25} - \sqrt{15}$

$9x = \dfrac{27 - 25\sqrt{15} }{25}$

Dividing both sides by 9:

$x = \dfrac{27 - 25\sqrt{15} }{225}$

Answer 2

Answer:

GIven:

\sqrt{ \bigg(5^0 + \dfrac{2}{3} \bigg) } = (0.6)^2 - 3x

(5

0

+

3

2

)

=(0.6)

2

−3x

To FInd:

The value of x

Solution:

\sqrt{ \bigg(5^0 + \dfrac{2}{3} \bigg) } = (0.6)^2 - 3x

(5

0

+

3

2

)

=(0.6)

2

−3x

Rewriting 5⁰ = 1:

\sqrt{ \bigg(1 + \dfrac{2}{3} \bigg) } = (0.6)^2 - 3x

(1+

3

2

)

=(0.6)

2

−3x

\sqrt{ \dfrac{5}{3} }= (0.6)^2 - 3x

3

5

=(0.6)

2

−3x

Rationalise the LHS by multiplying √3/√3:

\dfrac{\sqrt{15} }{3} = (0.6)^2 - 3x

3

15

=(0.6)

2

−3x

Rewriting (0.6)² as a fraction:

\dfrac{\sqrt{15} }{3} = \bigg( \dfrac{6}{10} \bigg)^2 - 3x

3

15

=(

10

6

)

2

−3x

\dfrac{\sqrt{15} }{3} = \dfrac{9}{25} - 3x

3

15

=

25

9

−3x

Multiply both sides by 3:

\sqrt{15} = \dfrac{27}{25} - 9x

15

=

25

27

−9x

Find x:

9x = \dfrac{27}{25} - \sqrt{15}9x=

25

27

−

15

9x = \dfrac{27 - 25\sqrt{15} }{25}9x=

25

27−25

15

Dividing both sides by 9:

x = \dfrac{27 - 25\sqrt{15} }{225}x=

225

27−25

15