Question

find the value of x and BD ​

Answer 1

Answer:

area of the triangle BCD is

1/2.8.10 sq unit

=40 sq unit

BCD is a right angle triangle

so, BC^2+CD^2=BD^2

=> 8^2+10^2=BD^2

=> 64+100=BD^2

=> BD^2=164

=> BD=√164=2√41

BD=2√41 unit

1/2.BD.x=40

=> x=40.2/BD

=> x=80/2√41=40/√41