find the value of x and measures of angle BAC and Angle ACD.
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2
angle A+B =180
(3x+15)+(2x+45)=180
5x+6o=180
x=120/5
x=24
A=87
B=93
(3x+15)+(2x+45)=180
5x+6o=180
x=120/5
x=24
A=87
B=93
Answered by
4
(3x+15)°+(2x+45)°=180°
=5x+60°=180°
=5x=180°-60°
=5x=120°
=x=120°/5
=x=24°
angle 1st =(3x+15°)
=(3×24°+15°)
=(72°+15°)
= 87°
angle 2nd=(2x+45°)
=(2×24°+45°)
=(48°+45°)
=93°
hope it helps you
=5x+60°=180°
=5x=180°-60°
=5x=120°
=x=120°/5
=x=24°
angle 1st =(3x+15°)
=(3×24°+15°)
=(72°+15°)
= 87°
angle 2nd=(2x+45°)
=(2×24°+45°)
=(48°+45°)
=93°
hope it helps you
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