Question

Find the value of X and show it

Answer 1

\/7y^2-6y-13\/7
=\/7y^2-13y+7y-13\/7
=y(\/7y-13)+\/7(\/7y-13)
=(y+\/7)(\/7y-13)

Answer 2

hi friend......✌✌✌✌✌


At first your question is wrong.........it should be Find the value of y


Now here is your answer.......⬇⬇⬇⬇

√7y²-6y-13√7=0
or, √7y²-13y+7y-13√7=0
or, y(√7y-13)+√7(√7y-13)=0
or, (y+√7)(√7y-13)=0


so, y+√7=0. or,√7y-13=0
or, y=-√7. or, y=13/√7



so the value of y=√7 or 13/√7



hope it helps you....☺☺☺☺