Question

find the value of x and the other two angles of the triangle . angle 1 is x angle 2 is 3x+7 and angle 3 is 2x - 19 remember the sum of total angles of a triangle is 180 degree plz tell me fast urgent
plz fast

Answer 1

$\textbf{\underline{\underline{Answer :-}}}$

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Given :-

• 3 angles of a triangle as x, (3x+7), (2x-19)

To Find :-

• All angles of the triangle

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As we know that sum of all angles of a triangle is 180°

Then,

x + (3x+7) + (2x-19) = 180°

= = > x + 3x + 7 + 2x - 19 = 180

= = > 6x - 12 = 180

= = > 6x = 180 + 12

= = > 6x = 192

= = > x = 192/6

= = > x = 32

= = > 3x + 7 => 3(32) + 7 => 96 + 7 => 103

= = > 2x - 19 = 2(32) - 19 => 64 - 19 => 45

Answer 2

Question :-

Find the value of x and the other two angles of the triangle. ∠1 is x, ∠2 is (3x + 7)° and ∠3 is (2x - 19)°.

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Given :-

• Three angles of a triangle as x°, (3x + 7)° and (2x - 19)°.

To Find :-

• Value of x and other angles of the triangle.

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Answer :-

We know that sum of angles of a triangle is 180°.

Then,

x + (3x + 7) + (2x - 19) = 180

➪ x + 3x + 7 + 2x - 19 = 180

➪ 6x - 12 = 180

➪ 6x = 180 + 12

➪ 6x = 192

➪ x = 192/6

➪ x = 32°

Put the value of x in the angles.

• x 32°

• 3x + 7 3(32) + 7 96 + 7 103°

• 2x - 19 2(32) - 19 64 - 19 45°

Hence, all angles of the traingle are 32°, 103°, 45° respectively.

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