find the value of x and y
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Step-by-step explanation:
6/x+y= 7/x-y +3
1/2(x+y)=1/3(x-y)
let 1/x+y be 'u' and 1/x-y be 'v'
6u=7v+3 or6u-7v=3 (eq 1)
1u/2=1v/3
cross multiply
3u=2v
v=3u/2
putting the value of v in eq 1 we get
6u-7*3u/2=3
as the LCM is 2
6u*2-21u=3*2
12u-21u=6
-9u=6
u=6/-9=-2/3
v=3u/2
v=(3* -2/3)/2
v=-2/2
v=-1
as 1/x+y=u
1/x+y= -2/3
x+y=-3/2 or 2x+2y= -3 (eq 2)
as 1/x-y=v
x-y=1/v
x-y=1/-1
x-y= -1 (eq 3)
from eq 2 and 3 we get
2x-2y= -3
(x-y= -1*)2
2x+2y= -3
2x-2y= -2
4x= -5
x=-5/4=-1.25
putting the value of x in eq 3 we get
-1.25-y=-1
-y=-1+1.25=0.25
y=-0.25
x=-1.25,y=-0.25
Anonymous:
thanks tia
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