Question

find the value of x and y

Answer 1

HELLO !!!
Here's Your Answer

>>--------☺--------<<

in triangle AOD

angle O = 90° ( given )
=> angle A + angle D = 90° ( angle sum property )

4y + 3y+6 = 90°

7y = 90-6

7y = 84

y = 84 ÷ 7

y = 12°

now, in triangle BOC

angle O = 90° ( V.O.A )
=> angle B + angle C = 90° ( angle sum property )

x-6 + x = 90°

2x-6 = 90°

2x = 90+6

2x = 96

x = 96÷2

x = 48°

hence, x = 48° and y = 12°........Ans

>>--------☺--------<<

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Answer 2

$heya \: dear \\ \\ \: here \: is \: your \: answer \\ \\ \\ we \: know \: that \:$
_________%_%__________⭐⭐⭐
AOB is a straight line,
⭐⭐⭐⭐⭐⭐⭐⭐⭐⭐⭐


THEN NOW,
∆AOD+∆DOB=180
90+∆DOB=180
∆DOB=180-90=90

⤵⤵⤵⤵⤵⤵⤵⤵⤵⤵⤵⤵⤵⤵⬇
IN STRAIGHT LINE DOC

∆AOD=∆COB (VERTICALLY OPPOSITE ANGLE)



⤵⤵⤵⤵⤵⤵⤵⤵⤵⤵
IN STRAIGHT LINE AOB

∆DOB=∆AOC (VERTICALLY OPPOSITE ANGLE)✔✔


IN ∆AOD
4Y+3Y+6+90=180
7Y+96=180
7Y=180-96
7Y=84
Y=84/7
Y=12✔✔



IN ∆COB,
90+X+X-6=180
2X+84=180
2X=180-84
X=96/2
X=48✔✔✔


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